IGNOU MTE 10 2018 - Solve x3 − 9x + 1 = 0 for the root lying between 2 and 4 by the

Question

Solve x³ − 9x + 1 = 0 for the root lying between 2 and 4 by the method of false position. Perform two iterations

14 Feb 2018

Answer :

Word Count : 293

We are asked to solve $x^3 - 9x + 1 = 0$ using the method of false position (regula falsi) for the root lying between 2 and 4. Let $f(x) = x^3 - 9x + 1$. Step 1: Check values at the endpoints $$ f(2) = 2^3 - 9(2) + 1 = 8 - 18 + 1 = -9 $$ $$ f(4) = 4^3

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IGNOU Solved Assignments Assignments Ignou Projects Project Previous Year Solved Exam Papers Notes Notes Sample Question Papers Sample Question Papers

x	1.0	1.2	1.4	1.6	1.8	2.0	2.2
f(x)	2.72	3.32	4.06	4.96	6.05	7.39	9.02

x	0.1	1.2	2.4	3.9
f(x)	3.41	2.68	1.37	-1.48

x	− 3	− 2	− 1	0	1	2	3
f ( x)	13	7	3	1	1	3	7