Question

Obtain the curl of the following vector field: A = (eˆ r + r cos θeˆ θ + r eφ)

25 Jan 2018
Answer :
Word Count : 385
To compute the curl of the given vector field \(\mathbf{A} = r \hat{e}_r + r \cos(\theta) \hat{e}_\theta + r \hat{e}_\phi\), we need to express it in cylindrical coordinates \((r, \theta, \phi)\) and apply the curl operator in these coordinates. ### Step 1: Curl in Cylindrical Coordinates The formula for the curl of a vector field \(\mathbf{A} = A_r \hat{e}_r + A_\theta \hat{e}_\theta + A_\phi \hat{e}_\phi\) in cylindrical coordinates is: \[ \nabla \times \mathbf{A} = \left( \frac{1}{r} \left( \frac{\partial A_\phi}{\partial \theta} - \frac{\partial A_\theta}{\partial \phi} \right) \right) \hat{e}_r + \left( \frac{1}{r} \left( \frac{\partial A_r}{\partial \phi} - \frac{\partial A_\phi}{\partial r} \right) \right) \hat{e}_\theta + \left( \frac{1}{r} \left( \frac{\partial A_\theta}{\partial r} - \frac{\partial A_r}{\partial \theta} \right) \right) \hat{e}_\phi \] ### Step 2: Components of \(\mathbf{A}\) We have the vector field: \[ \mathbf{A} = r \hat{e}_r + r \cos(\theta) \hat{e}_\theta + r \hat{e}_\phi \] From this,
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