Question
If X is a random variable with E(X) = 3and E(X2) = 16, find a lower bound for the probability P[-2 < X < 8].
Answer :
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Skip in 10
We are asked to find a lower bound for $P[-2 < X < 8]$ given $E(X) = 3$ and $E(X^2) = 16$. We can use Chebyshev's inequality for this purpose. First, calculate the variance of $X$: $$ \text{Var}(X) = E(X^2) - [E(X)]^2 = 16 - 3^2 = 16 - 9
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