Question

A particle describe a central orbit ra = aa cos n\theta under a force directed towards the pole. Find the law of Force.
(Rewrite the equation in terms of u = \frac{1}{r} , take logarithms and differentiate with respect to \theta . Calculate \frac{d^2 u}{d\theta } + u  and use 3a) to find F.)

15 Feb 2018
Answer :
Word Count : 516
To solve for the law of force for a particle describing a central orbit with the equation \( r^a = a^a \cos(n\theta) \), we'll follow these steps: ### Step 1: Rewrite the equation in terms of \( u = \frac{1}{r} \) The equation \( r^a = a^a \cos(n\theta) \) is given, and we need to rewrite it in terms of \( u = \frac{1}{r} \). So, we start by solving for \( r \): \[ r = \left( a^a \cos(n\theta) \right)^{1/a} \] Now, we can express \( u = \frac{1}{r} \): \[ u = \frac{1}{\left( a^a \cos(n\theta) \right)^{1/a}} = \left( a^a \cos(n\theta) \right)^{-1/a} \] Thus, we have: \[ u = \left( a^a \right)^{-1/a} \left( \cos(n\theta) \right)^{-1/a} = a^{-1} \left( \cos(n\theta) \right)^{-1/a} \] ### Step 2: Take logarithms Now, take the natural logarithm of both sides of the equation for \( u \): \[ \ln u = \ln \left( a^{-1} \left( \cos(n\theta) \right)^{-1/a} \right) \] \[
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