Question
Consider an operator for which
. Show that the expectation value of
in a parity eigenstate is zero.
Answer :
Word Count : 276
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Skip in 10
Let (\hat{O}) be an operator and (\hat{\pi}) the parity operator. The parity operator satisfies (\hat{\pi}^\dagger \hat{O} \hat{\pi} = -\hat{O}). Let (|\psi\rangle) be a parity eigenstate, so that (\hat{\pi}|\psi\rangle = \lambda |\psi\rangle), where (\lambda = \pm 1). The expectation value of (\hat{O}) in (|\psi\rangle) is: [ \langle \psi | \hat{O} | \psi \rangle ] Insert (\hat{\pi}^\dagger \hat{\pi} = I) (the identity) around (\hat{O}): [ \langle \psi | \hat{O} | \psi
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