Question

The lifespan (in ‘000 hours) of five LED bulbs of 07 watts are as follows:   40,   46,   48,  50,  42   

(i) How many samples of size 2 are possible without replacement? Write them.

(ii) Compute mean of all samples of size 2 and set up the sampling distribution of the sample mean.

(iii)Compute the expected value and standard error of the sample mean.

16 Feb 2018
Answer :
Word Count : 456
Let's solve the problem step by step numerically. --- ### Given Data: The lifespan (in ‘000 hours) of five LED bulbs: \[ 40, 46, 48, 50, 42 \] --- ### (i) Number of Samples of Size 2 Without Replacement: The number of ways to choose 2 samples from 5 without replacement is: \[ \text{Total Samples} = \binom{5}{2} = \frac{5!}{2!(5-2)!} = \frac{5!}{2!3!} = \frac{5 \times 4}{2 \times 1} = 10 \] The 10 possible samples (pairs) are: 1. (40, 46) 2. (40, 48) 3. (40, 50) 4. (40, 42) 5. (46, 48) 6. (46, 50) 7. (46, 42) 8. (48, 50) 9. (48, 42) 10. (50, 42) --- ### (ii) Compute the Mean of All Samples and Set Up Sampling Distribution The sample mean for each pair is: \[ \bar{x} = \frac{x_1 + x_2}{2} \] | Sample | Mean \(\bar{x}\) | |---------|----------------| | (40, 46) | \(\frac{40+46}{2}
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