Question

Check whether or not equation is a subgroup of

i) equation, equation      ii) equation

09 Jan 2026
Answer :
Word Count : 103
Consider (A={z\in\mathbb{C}^* \mid |z|\in\mathbb{Q}}). For ((\mathbb{C}^*,\cdot)): The set (A) is nonempty since (1\in A) and (|1|=1\in\mathbb{Q}). If (z,w\in A), then (|z|,|w|\in\mathbb{Q}), and (|zw|=|z||w|\in\mathbb{Q}), so (zw\in A); hence (A) is closed under multiplication. For
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