Question

The distribution function F of a continuous variable is given by

F(x) = 0, if x < 0

= x 2 , if 0 < x < 1

= 1 - \frac{3(3-X)^{2}}{25}, if \frac{1}{2}\leq x< 3

 

= 1, if x > 3

 

(i) Find the pdf of X,

(ii) Evaluate P[|X| <1/ 2], using distribution function F,

(iii) Evaluate P[|X| < 1/ 2], using pdf.

 

 

 

16 Feb 2018
Answer :
Word Count : 556
Let's break this down step by step based on the given distribution function \( F(x) \): ### (i) Find the pdf of \( X \): The probability density function (pdf) \( f(x) \) is the derivative of the cumulative distribution function (CDF) \( F(x) \). We will differentiate \( F(x) \) piece by piece. - For \( x < 0 \), \( F(x) = 0 \). The derivative of 0 is also 0, so: \[ f(x) = 0 \quad \text{for} \quad x < 0. \] - For \( 0 \leq x < 1 \), \( F(x) = x^2 \). The derivative of \( x^2 \) with respect to \( x \) is: \[ f(x) = 2x \quad \text{for} \quad 0 \leq x < 1. \] - For \( \frac{1}{2} \leq x < 3 \), \( F(x) = 1 - \frac{3(3-x)^2}{25} \). The derivative of this with respect to \( x
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