Question

If y = emtan -1 x , show that (1 + x2 ) y n+1 (2nx - m) yn n(n -1)y n -1 = 0.

01 Feb 2018
Answer :
Word Count : 457
Let's solve the given problem step by step. We are given the function \( y = e^{m \tan^{-1}(x)} \) and need to show the equation \[ (1 + x^2) y_{n+1} (2nx - m) y_n n(n - 1) y_{n-1} = 0. \] ### Step 1: Start with the given function \( y \) We are given that \[ y = e^{m \tan^{-1}(x)}. \] Now, we will find the derivatives of \( y \) with respect to \( x \). ### Step 2: First derivative of \( y \) Using the chain rule to differentiate \( y \), we get \[ \frac{dy}{dx} = \frac{d}{dx} \left( e^{m \tan^{-1}(x)}
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