Question

A light source of wavelength equation illuminates a metal surface and electron are ejected with the maximum kinetic energy 2 eV. If the same surface is illuminated by a light source of wavelength equation, then calculate the maximum kinetic energy of the ejected electron. (Work function of metal is 1 eV) 

21 Jan 2026
Answer :
Word Count : 111
For the photoelectric effect, the maximum kinetic energy of emitted electrons is given by (K_{\max} = h\nu - \phi = \dfrac{hc}{\lambda} - \phi). For light of wavelength (\lambda), the maximum kinetic energy is given as 2 eV and the work function (\phi) is 1
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