Question
Copper has a Debye temperature of 340 K and a Fermi temperature of 81000 K. At what temperature will the contribution of the vibrations of the crystal lattice (within the Debye theory) and that of the conduction electrons (within the free electron theory) to the specific heat become equal?
Answer :
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Let's solve this step by step, carefully, using manual calculation. We are asked: > Copper has a Debye temperature $\Theta_D = 340 \, \text{K}$ and a Fermi temperature $T_F = 81000 \, \text{K}$. At what temperature will the lattice vibrations contribution (Debye theory) and conduction electron contribution (free electron theory) to the specific heat become equal? --- ### Step 1: Write expressions for the specific heats 1. Lattice vibrations (Debye model): For $T \ll \Theta_D$ (low temperature), the specific heat of the lattice: $$ C_\text{lattice} = \frac{12 \pi^4}{5} N k_B \left(\frac{T}{\Theta_D}\right)^3 $$ where $N$ = number of atoms, $k_B$ = Boltzmann constant. --- 2. Conduction electrons (free electron model): For $T \ll T_F$, the electronic specific heat: $$ C_\text{electrons} = \frac{\pi^2}{2} N k_B \frac{T}{T_F} $$ --- ### Step 2: Equate the two contributions $$ C_\text{lattice} = C_\text{electrons} $$ $$ \frac{12 \pi^4}{5} N k_B \left(\frac{T}{\Theta_D}\right)^3 = \frac{\pi^2}{2} N k_B \frac{T}{T_F} $$ Cancel $N k_B$ on both sides: $$ \frac{12 \pi^4}{5} \left(\frac{T}{\Theta_D}\right)^3 = \frac{\pi^2}{2}
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