Question

A system having Weibull failure distribution with pdf as

f(t) = \frac{1}{\theta }e^\frac{-t}{\theta }t\geq 0

i) Compute the reliability function of the system,

ii) find the reliability for a 100 days mission for θ = 2,

iii) show that the hazard rate is constant,

iv) find the MTTF, and

v) what is the life of the system if reliability of 0.90 is desired.

17 Feb 2018
Answer :
Word Count : 524
Let's solve the problem step by step. ### Given: The probability density function (PDF) of the system follows a Weibull failure distribution: \[ f(t) = \frac{1}{\theta} e^{-\frac{t}{\theta}}, \quad t \geq 0 \] This is actually an exponential distribution, which is a special case of the Weibull distribution with shape parameter \( k = 1 \). --- ### (i) Compute the Reliability Function The reliability function, \( R(t) \), is the probability that the system survives beyond time \( t \). It is given by: \[ R(t) = P(T > t) = 1 - F(t) \] where \( F(t) \) is the cumulative distribution function (CDF), obtained by integrating the PDF: \[ F(t) = \int_0^t f(x) \,dx = \int_0^t \frac{1}{\theta} e^{-\frac{x}{\theta}} \,dx \] Solving the integral, \[ F(t) = \left[ -e^{-\frac{x}{\theta}} \right]_0^t \] \[ F(t) = 1 - e^{-\frac{t}{\theta}} \] Thus, the reliability function is: \[ R(t) = 1 - F(t) = e^{-\frac{t}{\theta}}
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