Question
एक पिंड सरल आवर्त गति करता है जिसकी आवृत्ति, , प्रारंभिक विस्थापन
तथा प्रारंभिक वेग
है। पिंड के दोलन का आयाम, अधिकतम वेग तथा अधिकतम त्वरण परिकलित करें।
Answer :
Word Count : 264
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पिंड का सरल आवर्त गति (SHM) इस प्रकार व्यक्त की जाती है: [ x(t) = A \cos(\omega t) + B \sin(\omega t) ] जहाँ ( \omega = 2 \pi f ) है। दी गई आवृत्ति ( f = 0.50 \text{ Hz} ) है। [ \omega = 2 \pi \times 0.5 = \pi \text{ rad/s} ] प्रारंभिक विस्थापन ( x_0 = 0.05 \text{ m} ) और प्रारंभिक वेग ( v_0 = 2.5 \text{ m/s} ) है। SHM में प्रारंभिक परिस्थितियों से हम आयाम ( X ) निकाल सकते हैं: [ x(0) = X \cos \phi = x_0 \implies X \cos \phi
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