Question

Consider the basis e1 = (−2, 4, −1), e2 = (−1, 3, −1) and e3 = (1, −2, 1) of R3

over R. Find the dual basis of {e1, e2, e3}.

02 Feb 2018
Answer :
Word Count : 638
To find the dual basis of the given set of vectors \( \{e_1, e_2, e_3\} \), we need to follow these steps: ### 1. Understand the problem: We are given the basis vectors: \[ e_1 = (-2, 4, -1), \quad e_2 = (-1, 3, -1), \quad e_3 = (1, -2, 1) \] These are vectors in \( \mathbb{R}^3 \), and we need to find the dual basis \( \{e_1^*, e_2^*, e_3^*\} \), which is the set of linear functionals that satisfy the following conditions: \[ e_i^*(e_j) = \delta_{ij} \] where \( \delta_{ij} \) is the Kronecker delta, which is 1 if \( i = j \) and 0 otherwise. ### 2. Setup the system of equations: The dual basis \( \{e_1^*, e_2^*, e_3^*\} \) must satisfy the condition: \[ e_i^*(e_j) = \delta_{ij} \] This means that the functional \( e_1^* \) should pick out the first component of \( e_1 \), and similarly for \( e_2^* \) and \( e_3^* \). Let: \[ e_1^* = (a_1, b_1, c_1), \quad e_2^* = (a_2, b_2, c_2), \quad e_3^* = (a_3, b_3, c_3) \] Now, we need to solve for the coefficients \( a_1, b_1, c_1, \dots, a_3, b_3, c_3 \) such that the conditions \( e_i^*(e_j) = \delta_{ij} \) are satisfied. ### 3.
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